用python实现跳一跳

下面是一个简单的 Python 实现跳一跳游戏的示例代码：
```python
import cv2
import numpy as np
import time
from pynput.mouse import Button, Controller
# 初始化鼠标控制器
mouse = Controller()
# 设置屏幕分辨率
screen_width, screen_height = 1920, 1080
# 调整棋盘的位置和大小
board_x = int(0.28 * screen_width)
board_y = int(0.63 * screen_height)
board_width = int(0.44 * screen_width)
board_height = int(0.32 * screen_height)
def get_board_center():
# 获取棋盘中心点的位置
center_x = board_x + board_width // 2
center_y = board_y + board_height // 2
return center_x, center_y
def jump(distance):
# 计算按压时长
press_time = int(distance * 1.35)
# 按住屏幕并松开
mouse.press(Button.left)
time.sleep(press_time / 1000)
mouse.release(Button.left)
# 使用OpenCV读取屏幕截图
def capture_screenshot():
screen = np.array(ImageGrab.grab(bbox=(0, 0, screen_width, screen_height)))
return cv2.cvtColor(screen, cv2.COLOR_BGR2RGB)
# 跳一跳主逻辑
def jump_game():
while True:
# 截取棋盘区域
screenshot = capture_screenshot()
board = screenshot[board_y:board_y+board_height, board_x:board_x+board_width]
# 使用OpenCV进行图像处理，获取棋子和目标方块的位置
gray = cv2.cvtColor(board, cv2.COLOR_BGR2GRAY)
ret, binary = cv2.threshold(gray, 200, 255, cv2.THRESH_BINARY)
contours, hierarchy = cv2.findContours(binary, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE)
if len(contours) > 1:
contours = sorted(contours, key=cv2.contourArea, reverse=True)
for contour in contours:
if cv2.contourArea(contour) > 50:
(x, y, w, h) = cv2.boundingRect(contour)
cv2.rectangle(board, (x, y), (x + w, y + h), (0, 255, 0), 2)
cv2.circle(board, (x + w // 2, y + h // 2), 3, (0, 0, 255), -1)
cv2.circle(board, get_board_center(), 3, (255, 0, 0), -1)
# 计算棋子和目标方块的距离并调用跳跃函数
distance = abs(x + w // 2 - get_board_center()[0])
jump(distance)
break
# 显示截图和处理后的图像
cv2.imshow("Screenshot", screenshot)
cv2.imshow("Board", board)
# 监听键盘事件，按下 q 键退出
if cv2.waitKey(1) & 0xFF == ord('q'):
break
# 释放资源
cv2.destroyAllWindows()
# 运行跳一跳游戏
jump_game()
```
代码中使用了 OpenCV 进行图像处理，需要额外安装 opencv-python 库。还使用了 pynput 库来进行鼠标控制，需要额外安装 pynput 库。
在运行代码之前，请确保已经正确安装了这两个库，并且屏幕分辨率的设置适用于你的屏幕。运行代码后，按下 `q` 键即可退出跳一跳游戏。